He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
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<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
Answer:
Adult= $11
Children = $7.5
Step-by-step explanation:
Let x represent adult ticket and y represent children ticket
2x + 3y= 44.50........equation 1
3x + 6y= 78........equation 2
From equation 1
2x + 3y= 44.50
2x= 44.50-3y
x= 44.50-3y/2
Substitute 44.50-3y/2 for x in equation 2
3x+ 6y= 78
3(44.50-3y/2) + 6y= 78
66.75- 4.5y +6y= 78
66.75 + 1.5y= 78
1.5y= 78-66.75
1.5y= 11.25
y= 11.25/1.5
y = 7.5
Substitute 7.5 for y in equation 1
2x + 3y = 44.50
2x + 3(7.5)= 44.50
2x + 22.5= 44.50
2x = 44.50-22.5
2x= 22
x= 22/2
x= 11
Hence the price of adult ticket is $11 and the price of children ticket is $7.5
Answer:
24xy+2y−234x2fromy+14x
Step-by-step explanation:
24xy−10y−(18×13)xxfromy+12y+14x
24xy−10y−234xxfromy+12y+14x
24xy−10y−234x2fromy+12y+14x
24xy+(−10y+12y)−234x2fromy+14x
Answer:
I think the answer is c = 25/4
Step-by-step explanation:
