Answer:
36°
Step-by-step explanation:
Please refer to the attached figure.
Triangles ANC, AMB, BCN, CBM are all isosceles by virtue of the given congruences. By symmetry, we also claim that ΔABC is isosceles (AB≅AC).
We aren't sure how their internal angles relate, but we can write a couple of equations.
Let x = m∠BAC, y = m∠BCN.
∠NCA = ∠NAC = ∠MBA = ∠MAB = x
∠BCM = ∠BMC = x +y
∠BMC = ∠MBA +∠MAB = 2x
So, we have ...
∠BMC = x +y = 2x ⇒ y = x
And the sum of angles around ΔABC is ...
x +(2x) +(2x) = 180°
x = 180°/5 = 36°
The measure of angle BAC is 36°.
Answer:
see explanation
Step-by-step explanation:
(1)
Given the perimeter then the third side is the perimeter subtract the sum of the 2 given sides, that is
third side
= 4x + 3y - (x - y + x + y)
= 4x + 3y - 2x ← collect like terms
= 2x + 3y
(2)
The area (A) of a triangle is calculated as
A =
bh ( b is the base and h the height )
Here b = 2x + 6 and h = x - 2, thus
A =
(2x + 6)(x - 2) ← expand factors using FOIL
=
(2x² + 2x - 12) ← distribute
= x² + x - 6 ← in standard form
Answer:
B
Step-by-step explanation:
2 || 1 - 4 6 - 4
2 -4 4
==================
1 -2 2
x^2 - 2x + 2 with no remainder.
Looks like the answer is B
Note: Note that the two in x - 2 changes sign. That always happens when using synthetic division as long the number in front of the x is positive.
Answer:
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