Solve : |3x-1/2| < 1 1/2

Mathematics

1 answer:

zysi [14]3 years ago

3 0

Answer:

\:0<x<\frac{1}{3}\:

Step-by-step explanation:

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Suppose a package delivery company purchased 17 trucks at the same time. Six trucks were purchased from manufacturer A, five fro

yaroslaw [1]

Answer:

$df_{den}=df_{between}=N-K=17-3=14$ .

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $3$ groups (A,B,C) and on each group we have sample of size (6,5,6) respectively , on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

The degrees of freedom for the numerator on this case is given by $df_{num}=df_{within}=k-1=3-1=2$ where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=17-3=14$ .

And the total degrees of freedom would be $df=N-1=17 -1 =16$

On this case the correct answer would be 2 for the numerator and 14 for the denominator.

Best answer

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3 years ago

Shaun estimated that the attendance at a

nevsk [136]

He rounded to the nearest thousand not the nearest percent. Please make me brainlest and have a good day

5 0

2 years ago

a big water tank contained 200 litres of water. during the day, 88 l 580 ml of water was used and 200 ml leaked. how much water

algol13

The quantity of water left in the tank as described in the task content is; 111 l 220ml.

<h3>What is the amount of water left in the tank?</h3>

The tank described in the task content initially contains 200 liters, in which case, 1 liter corresponds to 1000ml.

Hence, when 88l 580ml was used, the remaining quantity of water is; 200l - (88l 580ml) = 111 l 420ml.

And finally, since 200 ml leaked, the quantity of water left is; 111l 220ml.