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3 years ago

15

In a group 120 children there are teice as many boys as girls. How many girls are there?

2 answers:

Fudgin [204]3 years ago

8 0

Answer:

80 girls

Step-by-step explanation:

120/3 = 40.

40 x 2 = 80

3241004551 [841]3 years ago

6 0

Answer:

40 girls 80 boys

Step-by-step explanation:

80/2=40

40+80=120

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The cost per pound was roughly $0.41.

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2 years ago

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3 years ago

HELP PELASE ILL MARK BRAINLIEST AND POINTS!

UNO [17]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

$\qquad \sf \dashrightarrow \: x + y = 3$

put y = - 2,we will get :

$\qquad \sf \dashrightarrow \: x - 2 = 3$

$\qquad \sf \dashrightarrow \: x = 5$

so, 1st equation satifys the condition. let's check out 2nd one.

$\qquad \sf \dashrightarrow \: x + 2y = 1$

put y = -2

$\qquad \sf \dashrightarrow \: x + (2 \times - 2) = 1$

$\qquad \sf \dashrightarrow \: x - 4 = 1$

$\qquad \sf \dashrightarrow \: x = 5$

Hence, we can conclude that the Correct choice is D

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2 years ago

The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in

CaHeK987 [17]

Answer:

$\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

Step-by-step explanation:

The standard equation of the ellipse is

$\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)$

where, $(\alpha, \beta)$ is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, $(\alpha, \beta)=(-9,3)$ and major axis, $2a=24$ .

So, semi major axis, $a=24/2=12$ .

Now, focus of the ellipse is (-7,3).

Let $e$ be the eccentricity of the ellipse,

So, $e=\frac c a$

where $c$ is the distance between the center and focus of the ellipse.

By using the distance formula,

$c=\sqrt{(-9-(-7))^2+(3-3)^2}=2$

$\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)$

Again, the relationship among $a,b$ and $e$ is

$e=\sqrt{1-\frac{b^2}{a^2}$

$\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2}$ [from equation (ii)]

$\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144}$ [squaring on both the sides]

$\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}$

$\Rightarrow b^2=\frac{35}{36}\times144=140$

So, the value of square of semi-minir axis, $b^2=140$ .

Hence, from equation (i), the equation of required ellipse is standard form is

$\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1$

$\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1$

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3 years ago

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salantis [7]

1 hour=60 minutes
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3 years ago

Read 2 more answers