H(x) = 1/9000x^2 - 7/15x + 500 = 1/9000(x^2 - 4200x + 4500000) = 1/9000(x^2 - 4200x + 4410000 + 90000) = 1/9000(x - 2100)^2 + 1/9000(90000) = 1/9000(x - 2100)^2 + 10
h(x) = 1/9000(x - 2100)^2 + 10
Answer:
Step-by-step explanation:
Answer:
Point P
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
The graph is formed from f(x) = |x|.
f(x) = |x| is shaped like a V with the vertex at the origin and the slope of each arm = 1. Then f(x) = |x + 3| will have the same shape but will be moved 3 units to the left so the vertex is at (-3,0). The - 1 ( to give f(x) = |x + 3| - 1) translates the whole graph 1 unit down so the vertex is at the point (-3, -1).
The domain is All Real x and the range = All real values of f(x)
equal or greater than -1.
Answer:
The y-value of P' is -10.
Step-by-step explanation:
It was given that; triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2).
The translation rule is
To find the image of P, which is P', we have to substitute the coordinates of P(-2,6) to obtain;
Hence the y-value of P' is -10.
