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3 years ago

Find the exact,simplified value of x for the given triangle

Mathematics

1 answer:

Katarina [22]3 years ago

4 0

If this is a 30, 60, 90 triangle, which I think it is, it would b 4

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Given square PQRS, determine the missing information.

Julli [10]

Answer:

Step-by-step explanation:

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2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

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3 years ago

I really need help tyy

emmainna [20.7K]

Find the greatest common factor (gcf) in each grade between the girls and boys
in 6th grade the gcf is 8
64/8=8 72/8=9
the largest number of groups that can be made equally would be 8 groups of 8 girls and 8 boys
Hope this helps!!

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3 years ago

There are 5 slides, i've provided image for them all i need help with it. if your going to answer write it in order from slide 1

Nana76 [90]

Answer:

mark as brainleast and fo-ll-ow me

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3 years ago

Read 2 more answers

The circle below has a radius of 3 units . Find the area of the circle. Use 3.14 for π.

const2013 [10]

Answer:

28.26 units

Step-by-step explanation:

We know the radius of the circle is 3 units, so we'll end up plugging that into the formula.

A = π(3^2) or A = π * 3 * 3

When you substitute pi for 3.14, you'll end up getting 28.26 units.

Hope this helped! :)

6 0

2 years ago