The cross of heterozygous
AaBb as parental phenotype led to formation of 1
6 phenotype of the offspring.This is because this is dihybrid form of inheritance .The probability of having
aabb offspring is
1/16 since there is only one aabb type of offspring phenotype out of
the
16. An illustration of how crossing is done is as per punnet square below
C. protein synthesis (they make proteins)
Because l-glucose is toxic in nature.