Let x = length of the park
Let y = width of the park
Because the area is 392392 ft², therefore
xy = 392392 (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656 (2)
That is
y = 5656 - 2x (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
5656x - 2x² = 392392
2x² -5656x + 392392 = 0
x² - 2828x + 196196 = 0
Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
= 2756.83 or 71.17
Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
13
Explanation: a^2 + b^2 = c^2
12^2 + 5^2 = c^2
144 + 25 = c^2
/169 = c
c = 13
According to the information given, the system of inequalities that models the situation is given by:
<h3>System of inequalities:</h3>
For the system, the variables are:
- x is the number of hours that Pump 1 runs.
- y is the number of hours that Pump 2 runs.
They will run for at least 18 hours in a day but obviously no more than 24 hours in a day, hence:


Pump 1 can move 120 gallons per hour while Pump 2 can move 200 gallons per hour. In total the two pumps must move at least 3,000 gallons of water per day, hence:

You can learn more about system of inequalities at brainly.com/question/14361489