Answer:
29 and 35
Step-by-step explanation:
x+y=64
x-y=6
Solve by substitution.
x=6+y
6+y+y=64
6+2y=64
y=29
Then plug in 29 for y.
x+29=64 ......35
Answer:
C
Step-by-step explanation:
There has to be two variables it's being compared to, in which case this is the blood sugar level and the amount of sugar
We are given with
P(pop quiz) = 60%
P(not do homework) = 85%
And the condition that
P (pop quiz and do homework) > 5%
So,
P (pop quiz) x P (do homework)
P (pop quiz) x ( 1 - P (not do homework) )
60% x ( 1 - 85%)
The result is greater than five percent so he will not do his homework.
<h3>
Answer: 1</h3>
Point B is the only relative minimum here.
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Explanation:
A relative minimum is a valley point, or lowest point, in a given neighborhood. Points to the left and right of the valley point must be larger than the relative min (or else you'd have some other lower point to negate its relative min-ness).
Point B is the only point that fits the description mentioned in the first paragraph. For a certain neighborhood, B is the lowest valley point so that's why we have a relative min here.
There's only 1 such valley point in this graph.
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Side notes:
- Points A and D are relative maximums since they are the highest point in their respective regions. They represent the highest peaks of their corresponding mountains.
- Points A, C and E are x intercepts or roots. This is where the graph either touches the x axis or crosses the x axis.
- The phrasing "a certain neighborhood" is admittedly vague. It depends on further context of the problem. There are multiple ways to set up a region or interval of points to consider. Though visually you can probably spot a relative min fairly quickly by just looking at the valley points.
- If you have a possible relative min, look directly to the left and right of this point. if you can find a lower point, then the candidate point is <u>not</u> a relative min.
Answer:
71.123 mph ≤ μ ≤ 77.277 mph
Step-by-step explanation:
Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:
≤ μ ≤ 
Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and 
is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.
the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.
So, if we replace m by 74.2, s by 5.3083, n by 10 and 
by 1.8331, we get that the 90% confidence interval for the mean speed is:
≤ μ ≤ 
74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077
71.123 ≤ μ ≤ 77.277
