Q1=3 Q2[median]=12 Q3=14 and the IQR is 11
<u>Answer:</u>

<u>Step-by-step explanation:</u>
Given dimensions of the box = 20cm × 6cm × 4cm .
Dimension of the cube = 2cm × 2cm × 2cm .
Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,


<h3>
<u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>
Answer:
One.
Step-by-step explanation:
The reason why is because 12-5 = 7, meaning that your lowest length has to be 7. meaning, that you can only do one triangle.
Answer:
Think it's 109.33
Step-by-step explanation:
look it up brodie
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.