Answer:
Pure water =74.1 mL
Step-by-step explanation:
You need 420 mL of a 70% alcohol solution.
420 mL of solution and 70% of it should be alcohol.
So,
420 * 70/100 mL
= 420 * 0.7
= 294 mL of alcohol and the rest should be water.
On hand, you have a 85% alcohol mixture.
The alcohol can only come from the 85% mixture. So, how much of 85% alcohol do we need to get 294 mL of alcohol:
Let
y = alcohol solution needed
85% of y = 294
85/100 * y = 294
y = 294 ÷ 85/100
y = 294 × 100/85
y = 29,400/85
y = 345.88235294117
Approximately, 345.9mL
The rest of 420 mL solution has to be pure water
Pure water = 420 mL - 345.9mL
= 74.1 mL
Pure water =74.1 mL
Answer:
781000
Step-by-step explanation:
550000* 42%
231000+550000
(=^w^=)
Answer:
Distance xy = 11.66 unit (Approx)
Step-by-step explanation:
Given:
x(-7,10)
y(3,4)
Find:
Distance xy
Computation:
Distance = √(x2-x1)²+(y2-y1)²
Distance xy = √(3+7)²+(4-10)²
Distance xy = √ 100 + 36
Distance xy = 11.66 unit (Approx)
Answer:
(221.39, 300.61) and (255.2223, 266.7777)
Step-by-step explanation:
Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days
Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0
Corresponding we have x scores as
Between
and 
i.e. in the interval = (221.39, 300.61)
If sample size = 47, then std error of sample would be

So 98% of pregnancies would lie between
and 
= (255.2223, 266.7777)
I believe Maine Coone would weigh more because its mean is 6.2 and that is a greater amount than 3.