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Dmitry [639]
3 years ago
14

Select all that apply.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer: B, C, and E

Step-by-step explanation:

B and C are the same thing. And E will also work.

A will get you in the right quadrant, but the shape is wrong.

D will just get you back into the place you origianlly started at.

You might be interested in
The square with side length 2 cm is dilated by a scale factor of 7/3 is the dilated image larger or smaller than the original im
qwelly [4]
Length of square side= 2 cm
Dilation factor= 7/3
Simplify 7/3= 2.33
Apply the dilation factor:
Length of side= 2.33 x 2 = 4.67 cm
As the length of the side of the square is increased in length, which means the dilated image is larger than the original image.

Answer: Larger than then original. 
8 0
3 years ago
Maths help PLZZ!!!
Slav-nsk [51]

Triangle ABC is an isosceles triangle.

Solution:

Given data:

∠ABC = 70° and ∠ACD = 55°

<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>

m∠BAC = m∠ACD

m∠BAC = 55°

<em>Sum of the angles in a straight line add up to 180°.</em>

m∠ACD + m∠ACB + m∠ABC = 180°

55° + m∠ACB + 70° = 180°

m∠ACB + 125° = 180°

Subtract 125° from both sides, we get

m∠ACB = 55°

In triangle ABC,

∠BAC = 55° and ∠ACB = 55°

∠BAC = ∠ACB

Two angles in the triangle are equal.

Therefor triangle ABC is an isosceles triangle.

6 0
3 years ago
How do you solve this?
slavikrds [6]

Answer: To solve these types of questions what I always do is get a protractor if you have one and put it up against to where the dot is in the middle of the empty hole and then get a ruler or a pencil and make the line keep going to see what angle. In this case your answer is 65% I think.

4 0
3 years ago
If mABD​, what are mABC and m​DBC?
Sedbober [7]

Answer:

45

Step-by-step explanation:

8 0
3 years ago
The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea
Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that P(A \cap B) = 0.03

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that P(A) = 0.03 + 0.7 = 0.73

What is the probability of the following event: He has lung disease given that he does not smoke?

P(B|A) = \frac{0.03}{0.73} = 0.0411

4.11% probability that he has lung disease given that he does not smoke

5 0
3 years ago
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