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3 years ago

Select all that apply.

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer: B, C, and E

Step-by-step explanation:

B and C are the same thing. And E will also work.

A will get you in the right quadrant, but the shape is wrong.

D will just get you back into the place you origianlly started at.

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Find the value of z in the isosceles triangle shown below.<br> V20<br> V20<br> 8

Shkiper50 [21]

Answer:

Step-by-step explanation:

use Pythagorean theorem:

a² + b² = c²

where a = x

b = 8/2 = 4

c = √20

plugin values into the formula:

x² + 4² = (√20)²

x² + 16 = 20

x² = 20 - 16

x = √4

x = 2

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2 years ago

Find the roots of each equation by factoring

Aleksandr [31]

Answer:

x=2

Step-by-step explanation:

Solution is attached

You can plug 2 back into the equation to verify :)

3 0

2 years ago

He earns a fixed weekly salary of $300 plus a fee of $5 for each car he parks. His potential earnings for a week are shown in th

tamaranim1 [39]

I think what you are looking for is 5x=300 therefore x=60 so at 60cars he would start to make more.

3 0

2 years ago

A simple dart target has two concentric circles. The larger circle has a radius of 4. The smaller circle has a radius of 2. The

Natali5045456 [20]

Answer:

3 times more.

Step-by-step explanation:

The odds of landing a dart in any of the circles correspond to the surface area of the circle.

Calculate the surface area of both circles:

The formula for the area of a circle is $\pi r^{2}$ .

inner circle: $A=\pi 2^{2}=12.566$
for the outer circle, use the formula then subtract the value of the inner circle, to find the remaining area: $A=(\pi 4^{2} )-12.566=37.699$

Calculating greater chance:

Divide the larger area by the smaller area:

$37.699/12.566 = 3$

That means that the area of the outer circle is 3 times larger, making it 3 times more likely to hit the outer circle. Therefore the points for hitting the inner circle should be 3 times more.

7 0

2 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
</span>
hope this helps!

3 0

2 years ago