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3 years ago

What are the constants in the expression below? 12x -3.7 -8y +1/3

Mathematics

2 answers:

Fantom [35]3 years ago

7 0

The constants are -37 and 1/3

Fantom [35]3 years ago

5 0

Anything without a variable in front.

In other words, the constants are -3.7 and 1/3

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Reducing fraction 80/100

IceJOKER [234]

Answer:

4/5 is fully reduced

Step-by-step explanation:

4 0

3 years ago

If cos A = 3 over 11, then which of the following is correct?

ziro4ka [17]

Answer: The answer is (a) sec A = 11 over 3.

Step-by-step explanation: Given that Cosine of an angle 'A' is 3 over 11,

i.e.,

$\cos A=\dfrac{3}{11}.$

And we need to find which one of the given four options is correct.

We have the following relations between cosine, secant and cosecant of an angle from trigonometry.

$\sec A=\dfrac{1}{\cos A}~~\textup{and}~~\csc A=\dfrac{1}{\sqrt{1-\cos^2 A}}.$

Therefore,

$\sec A=\dfrac{11}{3}$

and

$\csc A=\dfrac{1}{\sqrt{1-\frac{9}{121}}}=\dfrac{1}{\sqrt{\frac{112}{121}}}=\dfrac{11}{4\sqrt 7}.$

Thus, the correct option is (a) sec A = 11 over 3.

3 0

4 years ago

Find a point-slope form for the line with slope 1/5 and passing through the point (-6,-9).

Elenna [48]

Answer:

y=1/5x-39/5

Step-by-step explanation:

y=mx+b (slope y intercept formula)

y=1/5x+b

take (-6,-9) and put in appropiate places

-9= -6/5+b

*multiply lhs and rhs by 5

-45= -6+5b

-45+6=5b

-39=5b

-5b=39

b=39/-5

y=1/5x-39/5

5 0

3 years ago

The vertical angle to the top of a flagpole from point A on the ground is observed to be 37°11'. The observer walks 17 m directl

inysia [295]

Answer:

22m

Step-by-step explanation:

Let height of flagpole=h

AB==17 m

$\angle CAD=37^{\circ}11'=37+\frac{11}{60}=37.183^{\circ}$ (1 degree= 60 minute)

$\angle B=25^{\circ}43'=25+\frac{43}{60}=25.72^{\circ}$

We have to find the approximate height of the flagpole.

In triangle CDA,

$\frac{CD}{DA}=tan\theta=\frac{Perpendicular\;side}{Base}$

$\frac{h}{DA}=tan37.183^{\circ}$

$h=DA(0.759)$

In triangle CDB,

$tan 25.72^{\circ}=\frac{CD}{DB}$

$0.482=\frac{h}{DA+17}$

$0.482DA+8.194=h$

Substitute the value

$0.482DA+8.194=0.759DA$

$8.194=0.759DA-0.482DA$

$8.194=0.277DA$

$DA=\frac{8.194}{0.277}=29.58$

Substitute the value

$h=29.58 \times 0.759=22.45 m\approx 22m$

Hence, the height of the flagpole=22 m

3 0

3 years ago

The graph shows how the distance an object traveled changed over time.

Pavlova-9 [17]

I believe the correct answer from the choices listed above is option D. The points where the object is traveling at the greatest speed would be <span>between points A and B because that slope is the steepest. The slope of this graph indicates speed since it will have the units of distance per time. The steeper the line is , the greater the value of the slope which would mean faster speed.</span>

4 0

4 years ago