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Sonja [21]
2 years ago
11

13(10 + 2) could be used to simplify which of the following problems?

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
6 0
Well first you need to show the rest of the problems before i can truely help you sorry.
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stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean (\mu) = 5.75913

Standard deviation (\sigma) = 0.172229

Variance (\sigma2) = 0.0296

Here we get is

a)

P(x < \mu - \sigma/2) = p(x < 5.673) \\\\          = 0.3085

b)

P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085

c)

P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383

d)

25th percentile:-

= 25*[(n+1)/100]th term \\\\= 5.69

75the percentile:-

= 75*[(n+1)/100]th term\\\\ = 5.87

e)  

p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707

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72= 18 x w

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width is 4 cm


 

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3 years ago
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