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muminat
2 years ago
7

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

erscript negative 12 Baseline q Superscript negative 3 Baseline EndFraction in simplified form? Assume p not-equals 0, q not-equals 0. Negative StartFraction 3 p Superscript 8 Baseline Over 4 q cubed EndFraction Negative StartFraction 3 Over 4 p Superscript 16 Baseline q Superscript 9 Baseline EndFraction Negative StartFraction p Superscript 8 Baseline Over 5 q cubed EndFraction Negative StartFraction 1 Over 5 p Superscript 16 Baseline q Superscript 9 Baseline EndFraction

Mathematics
2 answers:
Talja [164]2 years ago
7 0

can be simplified to

-\frac{3p^8}{4q^3}

Hopes this helps

if not then I'm sorrr

zhannawk [14.2K]2 years ago
3 0

Answer:

- \frac{3}{4} \times  \frac{p^{8} }{q^{3} }

Step-by-step explanation:

We have to find the quotient of the following division, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}.

Now, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}

= - \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]} {Since all the terms in the expression are in product form, so we can treat them separately}

{Since we know the property of exponent as \frac{a^{b} }{a^{c} } = a^{(b - c)}}

= - \frac{3}{4} p^{8} q^{-3}

= - \frac{3}{4} \times  \frac{p^{8} }{q^{3} } (Answer)

{Since we know, a^{-b} = \frac{1}{a^{b} }}

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Answer:

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And solving we have:

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Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

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4 0
3 years ago
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x is less than or equal to -4 or x is greater than or equal to 5

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Step-by-step explanation:

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