Question

3. Write an equation for the line perpendicular to y = 6x - 5 that contains (2, 10)

Answer 1

Answer:

$y = -\frac{1}{6}x +\frac{31}{3}$

Step-by-step explanation:

We are to find the equation for the line which is perpendicular to another line with the equation $y = 6x - 5$ and passes through a point (2, 10).

Since the slope of a line which is perpendicular to another line is the negative reciprocal of the other line, therefore the slope of our line will be $-\frac{1}{6}$.

Finding the y-intercept:

$y=mx+c$

$10=-\frac{1}{6} (2)+c$

$c=\frac{31}{3}$

Therefore, the equation of the line will be $y = -\frac{1}{6}x +\frac{31}{3}$.