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3 years ago

It's really important, please help

Mathematics

2 answers:

slavikrds [6]3 years ago

5 0

<em>The question isn't complete. This is just part of the question</em>

<em>So please send the whole question together.</em>

harina [27]3 years ago

3 0

Answer:

98 mins

Step-by-step explanation:

147.5 +x = 245.5

x = 245.5-147.5

x= 98 mins

You might be interested in

Complete the table of inputs for the given function.

Alecsey [184]

Answer:

a. $x = \frac{3}{8}$

b. $g(0) = 3$

c. $x = 1$

d. $g(3) = -21$

Step-by-step explanation:

Given

$g(x) = 3 - 8x$

Solving (a): When g(x) = 0

Substitute 0 for g(x)

$g(x) = 3 - 8x$

$0 = 3 - 8x$

Solve for 8x

$8x = 3$

Solve for x

$x = \frac{3}{8}$

Solving (b): when x = 0

Substitute 0 for x

$g(x) = 3 - 8x$

$g(0) = 3 - 8 * 0$

$g(0) = 3 - 0$

$g(0) = 3$

Solving (c): When g(x) = -5

Substitute -5 for g(x)

$g(x) = 3 - 8x$

$-5 = 3 - 8x$

Solve for 8x

$8x = 3 + 5$

$8x = 8$

Solve for x

$x = \frac{8}{8}$

$x = 1$

Solving (d): When x = 3

Substitute 3 for x

$g(x) = 3 - 8x$

$g(3) = 3 - 8 * 3$

$g(3) = 3 - 24$

$g(3) = -21$

3 0

3 years ago

Can anyone help me about question 2

madreJ [45]

9514 1404 393

Answer:

3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

$(a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}$

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

$\log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}$