Answer:
2.3
Step-by-step explanation:
Using SOH CAH TOA, we can label CB as the alternate side seeing as it's opposite to the known angle 50 degrees. We know AB is the hypotenuse since it's the longest side. Therefore CA must be the alternate side.
Since we want to know BC, and we know information about AB, we need to use the use of the hypotenuse and the opposite. In SOH CAH TOA, SOH uses both of these.
Using S O H, we understand that sin(50) * 3 = CB
Therefore CB = 2.3 to 1 decimal place.
Answer:
g = -3
Step-by-step explanation:
-7g + 5 = 2 – g – 7g
Combine like terms
-7g + 5 = 2 -8g
5 = 2 + -g
3 = -g
-3 = g
39 sides is the answer to it
Sum/difference:
Let
![x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}](https://tex.z-dn.net/?f=%20x%20%3D%205%20%2B%20%28-3%5Csqrt%7B8%7D%29%20%3D%205-3%5Csqrt%7B8%7D%20)
This means that
![3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}](https://tex.z-dn.net/?f=%203%5Csqrt%7B8%7D%20%3D%205-x%20%5Ciff%20%5Csqrt%7B8%7D%20%3D%20%5Cdfrac%7B5-x%7D%7B3%7D%20)
Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
![x = -15\sqrt{8}](https://tex.z-dn.net/?f=%20x%20%3D%20-15%5Csqrt%7B8%7D%20)
if again we assume x to be rational, we have
![\sqrt{8} = -\dfrac{x}{15}](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%7D%20%3D%20-%5Cdfrac%7Bx%7D%7B15%7D%20)
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.