The distance between the boat and the ocean's floor is 19m
<h3>
How to get the distance from the ship to the ocean's floor?</h3>
We can see this as a right triangle, where the rope with the anchor is the hypotenuse. So we already know that the hypotenuse measures 30m.
We also know an angle, it measures 39°, and we want to get the opposite cathetus to said angle (the height).
Then we use the relation:
Sin(a) = (opposite cathetus)/(hypotenuse).
Replacing the values that we know, we get:
Sin(39°) = d/30m
sin(39°)*30m = d = 18.9m ≈ 19m
The distance between the boat and the ocean's floor is 19m.
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
Answer:
A) A(t) = 4500*π - 1600*t
B) A(4) = 7730 in³
C) t = 8,8 sec
Step-by-step explanation:
The volume of the sphere is:
d max = 30 r max = 15 in
V(s) = (4/3)*π*r³ V(s) = (4/3)*π* (15)³
V(s) = 4500*π
A) Amount of air needed to fill the ball A(t)
A(t) = Total max. volume of the sphere - rate of flux of air * time
A(t) = 4500*π - 1600*t in³
B) After 4 minutes
A(4) = 4500*π - 6400
A(4) = 14130 - 6400
A(4) = 7730 in³
C) A(t) = 4500*π - 1600*t
when A(t) = 0 the ball got its maximum volume then:
4500*π - 1600*t = 0
t = 14130/1600
t = 8,8 sec
It’s d it’s d the answer is d
Answer:
First angle = 30°
Second angle = 60°
Third angle = 90°
Step-by-step explanation:
x + y + z = 180
y + z = 5x
z = y + 30
then:
y + (y+30) = 5x
2y + 30 = 5x
x = (2y+30)/5
then:
x + y + z = 180
{(2y+30)/5} + y + y+30 = 180
{(2y+30)/5} + 2y + 30 = 180
{(2y+30)/5} = 180 - 30 - 2y
{(2y+30)/5} = 150 - 2y
2y+30 = 5(150-2y)
2y+30 = 5*150 + 5*-2y
2y+30 = 750 - 10y
2y + 10y = 750 - 30
12y = 720
y = 720/12
y = 60°
x = (2y+30)/5
x = (2*60 + 30)/5
x = (120+30)/5
x = 150/5
x = 30°
z = y + 30
z = 60 + 30
z = 90°
Check:
x + y + z = 180°
30° + 60° + 90° = 180°
A to the power of b
a^b
a = base
b = exponent
SO
10^243 or 10 to the power of 243.
You can use other numbers also.
Hope i helped!!
