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3 years ago

8

The following graphs have no scales assigned to them. Which of them could be density curves for a continous random variable if t

hey were provided with the right scale.

2 answers:

34kurt3 years ago

8 0

Where are the graphs?

xxTIMURxx [149]3 years ago

4 0

Graph A, Graph D and Graph E

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Below is the graph of f(x)=2In(x). how would you describe the graph of g(x)=4In(x)

Andreyy89

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... with that template in mind, let's see yours

$\bf \begin{array}{llll}
g(x)=&4ln(x)\implies &2(2)ln(x)\\
&\uparrow &\uparrow \\
&A&A
\end{array}$

A is twice as large as in f(x), thus the graph shrinks twice as much in g(x)

7 0

4 years ago

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Evaluate log3 9 for me please<br><br> Answer choices:<br> 2<br> 3<br> 0.33<br> 0.5

asambeis [7]

The answer is letter choice A.

2

4 0

3 years ago

Read 2 more answers

Help me please.<br>Thank you.

Oksanka [162]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 4 parts red pigment = 8(4) parts of base = 32 parts of base

7 parts red pigment = 8(7) parts of base = 56 parts of base

12 parts red pigment = 8(12) parts of base = 96 parts of base

20 parts red pigment = 8(20) parts of base = 160 parts of base

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

How can you solve an equation without using the distributive property

belka [17]

You could use a calculator.. or if it is already in distributive property then just add it up

6 0

3 years ago

Complete the square to form a true equation;<br> x^2-2x+__=(x-__)^2

erica [24]

Answer:

see explanation

Step-by-step explanation:

To complete the square

add ( half the coefficient of the x- term )² to x² - 2x

x² + 2(- 1)x + 1

(x² - 2x + 1 = (x - 1)²

6 0

3 years ago