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PSYCHO15rus [73]
3 years ago
13

SOMBOSY HURRY UP AND HELP ME What is (7bp-2)+(3b+4)

Mathematics
2 answers:
amm18123 years ago
8 0

Answer:

7bp+3b+2

Step-by-step explanation:

we have

(7bp-2)+(3b+4)

Group terms that contain the same variable

(7bp)+(3b)+(-2+4)

combining like terms

(7bp)+(3b)+(2)

7bp+3b+2

STALIN [3.7K]3 years ago
7 0

(7bp-2)+(3b+4)

7bp-2+3b+4

7bp+3b+2

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Cathy sells an average of 32 pot holders each week.
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1500 pot holders

Step-by-step explanation:

32×48=1536 so it's about 1500 pot holders because 1536 it's closet to 1500

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Which of the following multiplication equations doesn't have the same solution as the others?
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The answer is option 2: 4b = 7. The other options all equal 4.
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What is 88 less than the product 13 times a number x is less than or equal to -32.
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Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −
Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

(x-h)^2+(y-k)^2=r^2

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

x^2 +y^2 - 4x+ 4y - 10 = 0  \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

x^2 +y^2 - 8x - 6y - 20 = 0   \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

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2 years ago
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Determine the value of the first term and write a recursive definition for the following
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It is just counting by 5.
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