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9514 1404 393
Answer:
38.2°
Step-by-step explanation:
The law of sines tells you ...
sin(x)/15 = sin(27°)/11
sin(x) = (15/11)sin(27°) . . . . . multiply by 15
x = arcsin((15/11)sin(27°)) ≈ arcsin(0.619078) ≈ 38.2488°
x ≈ 38.2°
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<em>Additional comment</em>
In "law of sines" problems, you need to identify a side and opposite angle that you know both values of. Then, you need to identify whether you're looking for an angle or a side, and whether its opposite side or angle is known. If two angles are known, you can always figure the third from the sum of angles in a triangle.
Here, we have angle 27° opposite side 11. We are looking for an angle, and we know its opposite side. This lets us use the ratio formula directly. Since the angle is the unknown, it is useful to write the equation with sines on top and sides on the bottom.
The given angle is opposite the shorter of the given sides, so this triangle has two solutions. We assume that we want the solution that is an acute angle (141.8° is the other solution). That assumption is based on the drawing. Usually, you're cautioned not to take the drawings at face value.
Answer:
Step-by-step explanation:
Probability that a person will not show up is,
P(person not show up)=0.098.
Probability that they will show up is
1-0.098=0.902
P(person will show up)=0.902
Jet passenger seat=18.
a. But is it wise to book 20 passenger seat
If the flight attendant book 20.
We want to know the probability that the two person will not show up.
The probability that the 2 person will not show up out of the 20 is given as
Using binomial distribution
Check attachment for formulas.
P(2 not showing up) =
20C2 • 0.098² • 0.902^20=0.2319
Which is 23.19% that the 2 person will not show up.
b. But is it wise to book 24 passengers for 22 jet seat.
The probability that the 2 will not show up out of the 24 is given as
Using binomial distribution
P(2 not showing up) =
24C2 • 0.098²• 0.902²²=0.2741
Which is 27.41% that the four person will not show up.
c. Probability of no enough seat
For 20 passengers and 18seats on jet
1-0.2319=0.7631.
For 24 passengers and 20 seats on jet
1-27.41=0.7259.
Then, It is not a wise decision because the probability that there are not enough seats on the jet is 0.7259 (72.59%). So, overbooking is an unlikely event.
