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Mashutka [201]
4 years ago
15

(2x3 + 3x2 + 10x)(8x4)

Mathematics
1 answer:
Alinara [238K]4 years ago
5 0

The simplified form of the given expression is \left(2^{3} \times x^{5}\right)\left(2 x^{2}+3 x+10\right)

<u>Step-by-step explanation:</u>

Given expression:

         \left(2 x^{3}+3 x^{2}+10 x\right)\left(8 x^{4}\right)

Now, we have to simplify the above so split into two term.

\left(2 x^{3}+3 x^{2}+10 x\right) can be written as below, ‘x’ is taken out as it is common.

          x\left(2 x^{2}+3 x+10\right) -----> eq. 1

8 x^{4} can be written as below, ‘8’ is cube of 2

          8 x^{4}=2^{3} \times x^{4} -----> eq 2

Now combine eq. 1 and 2, we get

         x\left(2 x^{2}+3 x+10\right)\left(2^{3} \times x^{4}\right)

When try to factoring 2 x^{2}+3 x+10, trinomial cannot be factored. Because,

  • Multiply the coefficient of the first term by the constant 2(10) = 20
  • Find two factors of  20 whose sum equals the coefficient of the middle term, which is 3. But no two such factors can be found.

Hence,

         \left(2^{3} \times x^{5}\right)\left(2 x^{2}+3 x+10\right)

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       log(2)/log(6)= x
                          x = 0.3868 = 0.39</span>
The answer to this question is A) (0.39, 0).
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Read 2 more answers
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
4 years ago
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