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tresset_1 [31]
3 years ago
5

10 Mason's can build a wall working 7 hours a day,in 12 days.In how many days can the work be completed by 14 persons working 8

hours a day?​
Mathematics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

7 hr * 12 days = 84 hours

10*84 = 840 man-hrs to build the wall

----

14 men * 8 hr = 112 man-hrs/day

840/112 = 7.5 days

Step-by-step explanation:

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For 20 points. Which point is a reflection of Z(5 1/2, 3) across the x-axis? Point A point B point C point D point E
Arturiano [62]
Its point c because you just make the 3 negative and c happens to be right on top of it
5 0
3 years ago
HELP ASAP!!!!! 18 Points!
Rasek [7]
Neither, tell me if I helped you
6 0
3 years ago
Read 2 more answers
4(4m-3)-m(m-5)=-52 need all the steps
nadezda [96]

\huge\mathcal {♨Answer♥}

\large\texttt{Simplifying: }

4(4m -3) + -1m(m + -5) = -52

\large\texttt{Reorder the terms: }

4(-3 + 4m) + -1(m + -5) = -52

(-3 * 4 + 4m * 4) + -1(m + -5) = -52

(-12 + 16m) + -1(m + -5) = -52

\large\texttt{Reorder the terms: }

-12 + 16m + -1(-5 + m) = -52

-12 + 16m + (-5 * -1 + m * -1) = -52

-12 + 16m + (5 + -1m) = -52

\large\texttt{Reorder the terms: }

-12 + 5 + 16m + -1m = -52

\large\texttt{Combine like terms: }

-12 + 5 = -7

-7 + 16m + -1m = -52

\large\texttt{Combine like terms: }

16m + -1m = 15m

-7 + 15m = -52

\large\texttt{Solving: }

-7 + 15m = -52

-7 + 7 + 15m = -52 + 7

\large\texttt{Combine like terms: }

-7 + 7 = 0

0 + 15m = -52 + 7

15m = -52 + 7

\large\texttt{Combine like terms: }

-52 + 7 = -45

15m = -45

\large\texttt{Divide each side by '15'. }

15m ÷ 15 = -45 ÷ 15

m = -3

\large\texttt{Simplifying: }

m = -3

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

_♡_<em>mashi</em>_♡_

8 0
2 years ago
13x + 5 + 17x -4.5 + x explain why this is wrong show your
alekssr [168]

The answerer is combining terms in x with constants

that is, 13x + 5 ≠ 18x

13x + 5 + 17x - 4.5 + x

= (13x + 17x + x ) + 5 - 4.5 ← collecting like terms

= 31x + 0.5 ← correct simplification





7 0
4 years ago
Read 2 more answers
Solve the following problems : Given: S, T, and U are the midpoints of RP , PQ , and QR respectively. Prove: △SPT≅△UTQ.
AleksandrR [38]

Answer:

Hence Proved △ SPT ≅ △ UTQ

Step-by-step explanation:

Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.

To prove: △ SPT ≅ △ UTQ

Proof:

∵ T is is the midpoint of PQ.

Hence PT = PQ    ⇒equation 1

Now,Midpoint theorem is given below;

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

By, Midpoint theorem;

TS║QR

Also, TS = \frac{1}{2} QR

Hence, TS = QU (U is the midpoint QR) ⇒ equation 2

Also by Midpoint theorem;

TU║PR

Also, TU = \frac{1}{2} PR

Hence, TU = PS (S is the midpoint QR) ⇒ equation 3

Now in △SPT and △UTQ.

PT = PQ (from equation 1)

TS = QU (from equation 2)

PS = TU (from equation 3)

By S.S.S Congruence Property,

△ SPT ≅ △ UTQ ...... Hence Proved

6 0
3 years ago
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