Answer:
Step-by-step explanation:
Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.
u = initial velocity = 30 : a = -g = 32 ft/sec^2
s(0) =initial height =4 ft.
We have the equation
where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration. Here final velocity is found out as follows
Substitute to get
Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.
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To reach 25 ft, put s = 25
and v must be atleast 0
Then we have
Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.
Answer:
The values of a and b are:
Step-by-step explanation:
We know that the slope-intercept form of the line equation
y = ax+b
where
From the diagram of the line graph, we can fetch the two points
Determining the slope between (0, 2) and (-1, 0)
Thus, the value of a = 2
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept b = 2
now substituting a = 2 and b = 2 in the slope-intercept form of the line equation
y = ax+b
y = 2x + 2 ∵ a = 2 , b = 2
Thus, the line of equation is:
y = 2x+2
now comparing with y = ax+b
Here:
a = 2
b = 2
Therefore, the values of a and b are:
How to solve your problem
x^{2}-21=100
Quadratic formula
Factor
1
Move terms to the left side
x^{2}-21=100
x^{2}-21-100=0
2
Subtract the numbers
x^{2}\textcolor{#C58AF9}{-21}\textcolor{#C58AF9}{-100}=0
x^{2}\textcolor{#C58AF9}{-121}=0
3
Use the quadratic formula
x=\frac{-\textcolor{#F28B82}{b}\pm \sqrt{\textcolor{#F28B82}{b}^{2}-4\textcolor{#C58AF9}{a}\textcolor{#8AB4F8}{c}}}{2\textcolor{#C58AF9}{a}}
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
x^{2}-121=0
a=\textcolor{#C58AF9}{1}
b=\textcolor{#F28B82}{0}
c=\textcolor{#8AB4F8}{-121}
x=\frac{-\textcolor{#F28B82}{0}\pm \sqrt{\textcolor{#F28B82}{0}^{2}-4\cdot \textcolor{#C58AF9}{1}(\textcolor{#8AB4F8}{-121})}}{2\cdot \textcolor{#C58AF9}{1}}
4
Simplify
Evaluate the exponent
Multiply the numbers
Add the numbers
Evaluate the square root
Add zero
Multiply the numbers
x=\frac{\pm 22}{2}
5
Separate the equations
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.
x=\frac{22}{2}
x=\frac{-22}{2}
6
Solve
Rearrange and isolate the variable to find each solution
x=11
x=-11
3rd and 5th one I think sorry if I’m wrong
