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ikadub [295]
3 years ago
8

Find f/g for the functions provided. 10 points Help needed.

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

ANSWER

( \frac{f}{g} )(x) =   \frac{1}{3} ( {x}^{2} + 3x + 9)

EXPLANATION

The given functions are

f(x) =  {x}^{3}  - 27

and

g(x) = 3x - 9

( \frac{f}{g} )(x) =  \frac{f(x)}{g(x)}

( \frac{f}{g} )(x) =  \frac{ {x}^{3}  - 27}{3x - 9}

( \frac{f}{g} )(x) =  \frac{ (x - 3)( {x}^{2} + 3x + 9) }{3(x -3 )}

Cancel the common factors,

( \frac{f}{g} )(x) =  \frac{  {x}^{2} + 3x + 9 }{3}

OR

( \frac{f}{g} )(x) =   \frac{1}{3} ( {x}^{2} + 3x + 9)

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Citrus2011 [14]

Hey there! I'm happy to help!

We start out with 3.

3

Our mom gives us 10.

3+10=13

Our dad gives us 30.

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43+100=143

And we have another 7.

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6 0
2 years ago
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Can i pls get help asap i will give brainly if the answer is right
Zanzabum
<h3>Answer:   0.5</h3>

This is equivalent to the fraction 1/2

==============================================================

Explanation:

The distance from A to B is 3 units. We can count out the spaces, or subtract the x coordinates of the two points and apply absolute value.

|A-B| = |-5-(-8)| = |-5+8| = |3| = 3

or

|B-A| = |-8-(-5)| = |-8+5| = |-3| = 3

We can say that segment AB is 3 units long.

--------------------------

The distance from A' to B' is 1.5 units because...

|A'-B'| = |-2.5-(-4)| = |-2.5+4| = |1.5| = 1.5

or

|B'-A'| = |-4-(-2.5)| = |-4+2.5| = |-1.5| = 1.5

The absolute values ensure the distance is never negative.

We can say A'B' = 1.5

---------------------------

Now divide the lengths of A'B' over AB to get the scale factor k

k = (A'B')/(AB)

k = (1.5)/(3)

k = 0.5

0.5 converts to the fraction 1/2.

The smaller rectangle A'B'C'D' has side lengths that are exactly 1/2 as long compared to the side lengths of ABCD.

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(f-g)(x) = x^4 - x^3 - 4x^2 - 3

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Answer:

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Step-by-step explanation:

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