<span>The normal approximation to a binomial can be used for a significance test on the population proportion p if np > 15.
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<span>a. n = 10 and H0: p = 0.4. => np = 10(0.4) = 4 [can not be used]
b. n = 100 and H0: p = 0.6. => np = 100(0.6) = 60 [can be used]
c. n = 1000 and H0: p = 0.996. => np = 1000(0.996) = 996 [can be used]
d. n = 500 and H0: p = 0.3.</span> => np = 500(0.3) = 150 [can be used0
6, if I get it wrong them I'm sorry
Steps to solve:
-6 + 2[6 + 4((-3)^2 - 7)]
~Solve exponent
-6 + 2[6 + 4(9 - 7)]
~Solve whats in parenthesis
-6 + 2[6 + 4(2)]
~Multiply
-6 + 2[6 + 8]
~Add
-6 + 2[14]
~Multiply
-6 + 28
~Add
22
Best of Luck!
Answer:
Hope this helps
Step-by-step explanation: