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FromTheMoon [43]
3 years ago
8

A bull’s-eye with a 4-inch diameter covers 20 percent of a circular target. What is the area, in square inches, of the target?

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0

Answer:

Area of target = 62.8 inch²

Step-by-step explanation:

A bull’s-eye with a 4-inch diameter covers 20 percent of a circular target.

Diameter of bull's eye = 4 inch

\texttt{Area of bull's eye = }\frac{\pi\times 4^2}{4}=12.56inch^2

Given that  bull’s-eye covers 20% of circular target.

\texttt{Area of bull's eye = }\frac{20}{100}\times \texttt{Area of target}\\\\\texttt{Area of target}\times 0.2=12.56\\\\\texttt{Area of target}=\frac{12.56}{0.2}=62.8inch^2

Area of target = 62.8 inch²

kipiarov [429]3 years ago
3 0

Area of a circle is found using the formula: Area = π * r^2

Using 3.14 for π

Area of the bull'e eye = π * 2^2 = 4π = 4 * 3.14 = 12.56 square inches.

This is 20% of the entire target.

To find the area of the entire target, divide the area of the bull's eye by the percentage:

Area = 12.56 / 0.20 = 62.8 square inches.

Round the answer as needed.

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The area of a circle is equal to the radius squared times pie, basically:

{r}^{2} \times \pi

The radius is 3, so we multiply 3 times 3 times pie to get the area.

You're gonna want to plug in the following into a calculator:

3 \times 3 \times 3.14

After getting 28.26 from such calculator, you need to round to the tenths place. In this number, the tenths place is the 2 next to the decimal on the right. Because the number after the 2 is a 6, that means we need to simplify the answer to (28.3). When you are rounding a number, you look at the number to the right, if it is 5 or bigger, add one and remove the rest, if it is less than 5, just get rid of the rest and leave it as it is.
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Arturiano [62]

Answer:

its A

Step-by-step explanation:

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Step-by-step explanation:

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3 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
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second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
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BabaBlast [244]
The answer is:
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8-8y+2y=11                   x=3
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So for my opinion the solution is A.(3,-1/2)
4 0
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