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3 years ago

PLEASE HELP ME

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

x = 0
x = 1

Step-by-step explanation:

Find two rows in the table that have the same values in the f(x) and g(x) columns.

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The answer is 5/4 in fraction form and 1.25 decimal form

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If $3,500 is invested at a rate of 6% , compounded continuously, approximately what amount of time would be needed to have a bal

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3 years ago

Find the mean and standard deviation for the set of data.

dem82 [27]

The mean and standard deviation for the set of data will be 16 and 5.87. Then the correct option is A.

<h3>What is a standard deviation?</h3>

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The set of data is given below.

16, 22, 8, 5, 20, 18, 14, 17, 24

The mean of the data set will be

μ = (16 + 22 + 8 + 5 + 20 + 18 + 14 + 17 + 24) / 9

μ = 144 / 9

μ = 16

Then the standard deviation of the data set will be

$\rm \sigma = \sqrt{\dfrac{\Sigma (x_i - \mu)^2}{n}} \\\sigma = \sqrt{\dfrac{(16 - 16)^2 +(22 - 16)^2 + (8-16)^2 + ......+(24-16)^2 }{9}} \\\sigma = \sqrt{\dfrac{310}{9}}\\$

Simplify the expression further, then we have

σ = √34.44

σ = 5.87

The mean and standard deviation for the set of data will be 16 and 5.87.

Then the correct option is A.

More about the standard deviation link is given below.

brainly.com/question/12402189

#SPJ1

3 0

1 year ago

What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f

ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

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3 years ago

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3 years ago