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Fittoniya [83]
3 years ago
10

Arrange these functions from the greatest to the least value based on the average rate of change in the specific interval

Mathematics
1 answer:
oee [108]3 years ago
5 0
The average r. of c. of a function f(x) on an interval [a,b] is:

  f(b) - f(a)
--------------
    b-a

You'll need to apply this to all four of the given functions.

First function:  f(x) = x^2 + 3x
a= -2; b= 3

Then the ave. r. of c. for this function on this interval is:

    18  - (-2)            20
------------------ = ---------- = 4.  y increases by 4 for every unit increase in x.
      3-(-2)                5

Do the same thing for the other 3 functions.

Then arrange your four results in descending order (greatest to least).

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Find the equation of the line with slope m=1/2 that contains the point (4,6)
vazorg [7]

Answer:

y = 1/2x + 4

Step-by-step explanation:

Use the formula for the equation of a line.

y = mx + b

Where m is the slope, and b is the y-intercept.

The slope is given.

y = 1/2x + b

The points (x, y) are given.

(4, 6)

Put y as 6 and x as 4, solve for b.

6 = 1/2(4) + b

6 = 2 + b

6 - 2 = b

4 = b

The y-intercept is 4 or (0, 4).

The equation of the line is y = 1/2x + 4.

4 0
3 years ago
What number should go in the space?<br> Multiplying by 1.75 is the same as increasing by _____%.
chubhunter [2.5K]

Answer:75%

Step-by-step explanation:

3 0
3 years ago
The distance between point Q and point P is 6 1/2 units .Which number could represent point Q?please help me
Elden [556K]

Answer: Zero and Any real number

Step-by-step explanation:

Point Q could be represented by any real numbers. And zero if it's located at the origin. The same is applicable to value at point P. It's just that at P, the value can't be equal to Zero.

5 0
3 years ago
Find the oth term of the geometric sequence 5,--25, 125,
Genrish500 [490]

Given the geometric progression below

5,-25,125,\ldots

The nth term of a geometric progression is given below

T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}

From the geometric progression, we can deduce the following

\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}

To find the value of r, we will take ratios of two consecutive terms

\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}

To find the 9th term of the geometric, we will have that;

\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}

Hence, the 9th term of the geometric progression is 1953125

8 0
1 year ago
1
8090 [49]

66666666666666666666

4 0
3 years ago
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