Consider the relationship between the place values of the 3s in this number.

Help plzz! True or False? -15 is a solution for -8x = 125

dmitriy555 [2]

Answer:

false, it doesn't equal 125

4 0

3 years ago

Read 2 more answers

The dimensions of the flat roof on a dog house are 4 feet by 6 feet

pantera1 [17]

The answer is B. Since the tile only has 2 dimensions, it is squared. Hope this helps!!! :)

3 0

3 years ago

A company has 10 male and 11 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many di

Anvisha [2.4K]

2475 different teams can be formed.

Combination is the way in which items can be selected from a collection. If we have n total objects and r objects want to be selected, the number of combinations is:

$C(n,r)=\frac{n!}{(n-r)!(r)!}$

Since we need to nominate 2 men from a company of 10 males, the number of ways this can be done = $C(10,2)=\frac{10!}{(10-2)!(2)!} =45\ ways$

Also, we need to nominate 2 women from a company of 11 females, the number of ways this can be done = $C(10,2)=\frac{11!}{(11-2)!(2)!} =55\ ways$

Therefore the total number of different teams that can be formed = 45 ways * 55 ways = 2475 ways

Find more at: brainly.com/question/8018593

3 0

3 years ago

Multiply and write your answer in a scientific notation. Take a look at the image!

DaniilM [7]

Answer:

12

Step-by-step explanation:

4 0

3 years ago

Data collected by the Substance Abuse and Mental Health Services Administration (SAMSHA) suggests that 69.7% of 18-20-year-olds

Lena [83]

Answer:

(a) Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.

(b) The probability that exactly 6 out of 10 randomly sampled 18- 20-year-olds consumed an alcoholic drink is 0.203.

(c) The probability that exactly 4 out of 10 randomly sampled 18- 20-year-olds have not consumed an alcoholic drink is 0.203.

(d) The probability that at most 2 out of 5 randomly sampled 18-20-year-olds have consumed alcoholic beverages is 0.167.

Step-by-step explanation:

We are given that data collected by the Substance Abuse and Mental Health Services Administration (SAMSHA) suggests that 69.7% of 18-20-year-olds consumed alcoholic beverages in 2008.

(a) The conditions required for any variable to be considered as a random variable is given by;

The experiment consists of identical trials.

Each trial must have only two possibilities: success or failure.

The trials must be independent of each other.

So, in our question; all these conditions are satisfied which means the use of the binomial distribution is appropriate for calculating the probability that exactly six consumed alcoholic beverages.

Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.

(b) Let X = Number of 18- 20-year-olds people who consumed an alcoholic drink

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,......$

where, n = number of trials (samples) taken = 10 people

r = number of success = exactly 6

p = probability of success which in our question is % 18-20

year-olds consumed alcoholic beverages in 2008, i.e; 69.7%.

So, X ~ Binom(n = 10, p = 0.697)

Now, the probability that exactly 6 out of 10 randomly sampled 18- 20-year-olds consumed an alcoholic drink is given by = P(X = 6)

P(X = 3) = $\binom{10}{6}\times 0.697^{6} \times (1-0.697)^{10-6}$

= $210\times 0.697^{6} \times 0.303^{4}$

= 0.203

(c) The probability that exactly 4 out of 10 randomly sampled 18- 20-year-olds have not consumed an alcoholic drink is given by = P(X = 4)

Here p = 1 - 0.697 = 0.303 because here our success is that people who have not consumed an alcoholic drink.

P(X = 4) = $\binom{10}{4}\times 0.303^{4} \times (1-0.303)^{10-4}$

= $210\times 0.303^{4} \times 0.697^{6}$

= 0.203

(d) Let X = Number of 18- 20-year-olds people who consumed an alcoholic drink

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r}; x = 0,1,2,......$

where, n = number of trials (samples) taken = 5 people

r = number of success = at most 2

p = probability of success which in our question is % 18-20

year-olds consumed alcoholic beverages in 2008, i.e; 69.7%.

So, X ~ Binom(n = 5, p = 0.697)

Now, the probability that at most 2 out of 5 randomly sampled 18-20-year-olds have consumed alcoholic beverages is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 3)

= $\binom{5}{0}\times 0.697^{0} \times (1-0.697)^{5-0}+\binom{5}{1}\times 0.697^{1} \times (1-0.697)^{5-1}+\binom{5}{2}\times 0.697^{2} \times (1-0.697)^{5-2}$

= $1\times 1\times 0.303^{5}+5 \times 0.697^{1} \times 0.303^{4}+10\times 0.697^{2} \times 0.303^{3}$

= 0.167

7 0

4 years ago