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barxatty [35]
3 years ago
8

What is the slope of the line passing through the points (2, 4) and (5, 6)?

Mathematics
2 answers:
STatiana [176]3 years ago
7 0
Hello there!

Your correct answer would be the last option.

2/3 would be your correct answer.
Andreyy893 years ago
3 0
The slope is 2/3

Hope I helped!

Let me know if you need anything else!

~ Zoe
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The video club to which Lin belongs allows her to receive one free DVD for every three DVDS she rents. If she pays $3 for each D
Nesterboy [21]

Answer:

12

Step-by-step explanation:

Given:

On every 3 DVDs she rents, 1 DVD is received for free

Rent of each DVD = $3

Total amount paid = $114

Now,

The total number of DVDs she took on rent = \frac{\textup{Total amount paid}}{\textup{Rent of each DVD}}

or

The total number of DVDs she took on rent = \frac{\textup{114}}{\textup{3}}

or

The total number of DVDs she took on rent = 38

also,

For every 3 DVDs she gets 1 Free DVD

thus,

For every 1 DVD she gets \frac{\textup{1}}{\textup{3}} free DVD

therefore,

For  38 DVD she gets \frac{\textup{38}}{\textup{3}} free DVD

or

she gets 12.67 DVDs free

Since,

the DVDs cannot be given in fraction

Hence she will get 12 free DVDs

5 0
3 years ago
(20,19),(-2,5)<br> Find the slope of the line through each pair of points
crimeas [40]
.............. M = 7/11
7 0
3 years ago
Read 2 more answers
5s=13 what is the answer
Alisiya [41]
S= 13/5 is the answer
I hope it’s help u !
8 0
2 years ago
I NEED MENNTAL HAELP
vekshin1

Answer:

Ummm Lilly Are you the one that I was jus talkin too

Step-by-step explanation:

6 0
2 years ago
For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
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