Right triangle ACB has side lengths c = 17 inches and a = 8 inches

1 answer:

5 0

A²+b²=c²

Where a=leg, b=base, and c=hypotenuse.

So, because we are given the side lengths of c and a, we simply plug everything in, and try to find b.

a²+b²=c²

8² + b² = 17²

Simplify.

64 + b² = 289

Subtract 64 from both sides.

b² = 289 - 64

Simplify.

b² = 225

b = $\sqrt{225}$

So, b = 15 inches

~Hope I helped!~

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