Ask question

Ask question

All categories

3 years ago

9

Right triangle ACB has side lengths c = 17 inches and a = 8 inches

1 answer:

Tasya [4]3 years ago

5 0

A²+b²=c²

Where a=leg, b=base, and c=hypotenuse.

So, because we are given the side lengths of c and a, we simply plug everything in, and try to find b.

a²+b²=c²

8² + b² = 17²

Simplify.

64 + b² = 289

Subtract 64 from both sides.

b² = 289 - 64

Simplify.

b² = 225

b = $\sqrt{225}$

So, b = 15 inches

~Hope I helped!~

You might be interested in

Write a system of equations to model each situation. Solve using any method:

ivolga24 [154]

Answer:

a=50 b=20

Step-by-step explanation:

Call A and B the 2 present ages.

Ten years from now, A is twice as old as B -->

(A + 10) = 2(B + 10) (1)

Five years ago, A was 3 times as old as B -->

(A - 5) = 3(B - 5) (2).

Solve the system (1) and (2).

From (2) --> A = 3B - 15 + 5 = 3B - 10.

Replace this value of A into (1) -->

3B - 10 + 10 = 2B + 20 --> B = 20. Then,

A = 3B - 10 = 60 - 10 = 50.

Check

!0 years from now --> A = 60 and B = 30 --> A = 2B .OK

5 years ago --> A = 45 and B = 15 --> A = 3B. OK

6 0

3 years ago

If an arithmetic progression satisfies U4=7 , U8=15 .Find U10

Alja [10]

<em>Answer:</em>

<em>U10 = 19</em>

<em>Step-by-step explanation:</em>

<em>The sequence is </em> $Ux=(x*2)-1$ <em />

<em>x is the coefficient to U.</em>

<em>So, </em> $U10=(10*2)-1$ <em />

<em>Which means </em> $U10=20-1$ <em />

<em>Which means </em> $U10=19$ <em />

<em>And there is your answer.</em>

<em>Hope this helps. Have a nice day.</em>

6 0

2 years ago

This maximization linear programming problem is not in "standard" form. It has mixed constraints, some involving ≤ inequalities

stellarik [79]

Answer: See Annex

z (max) = 190

x = 10

y = 20

Step-by-step explanation:

z = 5*x + 7*y to maximize

Subject to:

x + y ≤ 30

2*x + y ≤50

2*x - y ≥ 0

x≥= y ≥0

5 0

3 years ago

What value of n makes the equation true?

Anastasy [175]

Answer:

6

Step-by-step explanation:

$(4^{3} /4)^{3} = 4^{n} \\(4^{2})^{3} = 4^{n} \\4^{6} = 4^{n} \\n=6$

5 0

3 years ago

The picture frames shown are both squares. The area of the smaller frame is 1/4 the area of the larger frame. Find the side leng

baherus [9]

Area of smaller frame =1/4×36=9sq.in
side of smaller frame =
$\sqrt{9 } = 3in$
side of larger frame
$= \sqrt{36} = 6in$

4 0

4 years ago