Because 10 divided by 6 equals 6 tenths not 6 hundredths
Given:
The given equation is
![2x^3-3x^2+18x-27=0](https://tex.z-dn.net/?f=2x%5E3-3x%5E2%2B18x-27%3D0)
To find:
All the real solutions.
Solution:
We have,
![2x^3-3x^2+18x-27=0](https://tex.z-dn.net/?f=2x%5E3-3x%5E2%2B18x-27%3D0)
It can be written as
![x^2(2x-3)+9(2x-3)=0](https://tex.z-dn.net/?f=x%5E2%282x-3%29%2B9%282x-3%29%3D0)
![(2x-3)(x^2+9)=0](https://tex.z-dn.net/?f=%282x-3%29%28x%5E2%2B9%29%3D0)
Using zero product property, we get
and ![(x^2+9)=0](https://tex.z-dn.net/?f=%28x%5E2%2B9%29%3D0)
and ![x^2=-9](https://tex.z-dn.net/?f=x%5E2%3D-9)
and ![x=\pm\sqrt{-9}](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7B-9%7D)
We know that
is an imaginary number because there is a negative sign under the square root.
Therefore,
is the only real solution of the given equation.
Answer:
the second and thrid one :)
Step-by-step explanation:
Answer:
Arc CDE and arc EAC.
Step-by-step explanation:
Semicircles are exactly one-half of a circle and are always equal to 180 degrees. Since line CE is a horizontal line, measuring 180 degrees, 2 semicircles can be arcs CDE and EAC because they equal half of the circle.
I hope this helps!