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vekshin1
2 years ago
12

If an arithmetic progression satisfies U4=7 , U8=15 .Find U10​

Mathematics
1 answer:
Alja [10]2 years ago
6 0

<em>Answer:</em>

<em>U10 = 19</em>

<em>Step-by-step explanation:</em>

<em>The sequence is </em>Ux=(x*2)-1<em />

<em>x is the coefficient to U.</em>

<em>So, </em>U10=(10*2)-1<em />

<em>Which means </em>U10=20-1<em />

<em>Which means </em>U10=19<em />

<em>And there is your answer.</em>

<em>Hope this helps. Have a nice day.</em>

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Sandile bought 58 pies, each pie cost R68 each. estimate the total price of the pies..​
podryga [215]
Answer: 3944
All you have to do is multiply 58 x 68 to get the answer.
( hope this helped! )

5 0
2 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
I need help with 8-11....
MaRussiya [10]
8. Quadrants
9. Proportion
10. Proportionality
11. Dimensional analysis
8 0
3 years ago
Its for science but its got math involved<br>its got to do with speed distance and time​
KIM [24]
<h3>for 1</h3>

distance:1, 1, 1.3, 1.5, 2, 2.3, 2.5, 3 ,3.2, 4

time. :1, 2, 3 , 4 , 5 , 6 , 7 , 8 ,. 9 ,10

<h3>for 2</h3>

distance:1.5, 2, 3.2, 4.2, 5, 6, 7, 8

time. : 1 , 2, 3 , 4. , 5, 6, 7, 8

<h3>at 5 seconds which travelled the greatest distance : snail 2</h3>

<h3>which travelled a greater distance:snail 2</h3>

<h3>what is the speed of snail 1 at 8 second :</h3>

distance = 3. Time = 8

speed = distanc<em>e</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>ti</em><em>me</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>spee</em><em>d</em><em> </em><em>=</em><em> </em><u>8</u>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em>

<em>sp</em><em>eed</em><em> </em><em>=</em><em>2</em><em>.</em><em>6</em><em>6</em><em> </em>

<em>approximately</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>7</em><em>. </em><em> </em><em>or</em><em> </em><em>3</em>

7 0
3 years ago
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