Answer: the number is 369
Step-by-step explanation:
Let the missing number be y
8/9 × y = 328
8/9y = 328
Divide both sides by 8/9
y = 328 ÷ 8/9
y = 328 × 9/8 (multiply the two numerators: 328 x 9= 2952
Multiply the denominator by 1: 8 x 1= 8
Therefore y = 2952/8
y = 369
I hope this helps.
Answer:
B!!!
Step-by-step explanation:
Hopefully this helps
C=10
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.