Question

which shows a graph of a linear equation in standard form Ax+By=C , where A=0, B is positive , and C is negative ?

Answer 1

Ax+By=C , where A=0, B is positive , and C is negative

so y = - C/B (less than 0)

So answer is the last one. (y = -3)

Answer 2

Answer:In last graph y = -3 is the graph of linear equation Ax+By=C.

Step-by-step explanation:

Given: Linear equation in standard form Ax+By=C , where A=0, B is positive , and C is negative .

To find : Which graph show the equation .

Solution : We have given that Ax+By = C.

Where, A = 0 ,  B = positive , C = negative .

Plugging A = 0 , C = negative .

                   0 x +By = C.

               y = $\frac{-C}{B}$.

We can see y would be negative .

Therefore , In last graph y = -3 is the graph of linear equation Ax+By=C.