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lubasha [3.4K]
3 years ago
15

Please answer this question now

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
7 0

Answer:

397.7 m²

Step-by-step Explanation:

Step 1: find m < W

W = 180 - (33+113) (sum of ∆)

W = 34°

Step 2: find side UV using the law of sines

\frac{UV}{sin(W)} = \frac{VW}{sin(U)}

\frac{UV}{sin(34)} = \frac{29}{sin(33)}

Multiply both sides by sin(34)

\frac{UV}{sin(34)}*sin(34) = \frac{29}{sin(33)}*sin(34)

UV = \frac{29*sin(34)}{sin(33)}

UV = 29.8 m (approximated)

Step 3: find the area using the formula, ½*UV*VW*sin(V)

area = ½*29.8*29*sin(113)

Area = 397.7 m² (rounded to the nearest tenth.

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Step-by-step explanation:

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3 years ago
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Arte-miy333 [17]

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<u>Find the length of the segment AB</u>

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AB^{2} =AD^{2}+BD^{2}

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substitute the values

AB^{2}=5^{2}+12^{2}

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Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

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cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

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DC=AC-AD

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BC=31.2\ units

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