Step-by-step explanation:
Given :
log(a) + log(b) + log(c) = log(a + b + c)
We know that by property
log(a) + log(b) + log(c) = log(abc)
Therefore,
log(abc) = log(a + b + c)
Thus,
(abc) = (a + b + c)
Thus when a = b = c = 0,
then (abc) = (a + b + c)
0 = 0
and when a = 1, b = 2, c = 3,
then (abc) = (a + b + c)
(1 x 2 x 3 ) = (1 + 2 + 3)
6 = 6
The correct answer for the exercise shown above is the first option and the las option, which are:
<span>y = 3x + 20
3x - y = -20
</span>
The explanation is shown below:
1. You have the folllowing expression given in the problem above:
y-2=3(x+6)
2. If you solve it for y, you have:
y-2=3x+18
y=3x+18+2
y=3x+20
3. And if you move the variables to the left member, you have:
3x-y=-20
Therefore, as you can see, the correct answer are the options mentioned above.
You would need to go in the order of pemdas
X + y = 24....multiply by -3
3x + 5y = 100
---------------
-3x - 3y = - 72 (result of multiplying by -3)
3x + 5y = 100
--------------add
2y = 28
y = 28/2
y = 14
x + y = 24
x + 14 = 24
x = 24 - 14
x = 10
solution is (10,14)...and x represents 3 point q's and y represents 5 point q's......so this tells me there are 10 three point q's and 14 five point q's.
Answer:
radius = 11
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ( where r is the radius )
x² + y² = 121 ← is the equation of a circle centred at the origin
with r² = 121 , then
r = 
= 11
