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Olenka [21]
2 years ago
9

- 3m + 7 - 2n Can I get the answer

Mathematics
1 answer:
Aleks [24]2 years ago
3 0

Answer:

3m + 5

Step-by-step explanation:

uhmm i think 2n is i cant solve here hope it helps

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Can I get help on 6 and 7
Aloiza [94]
The cost depend on the number pencils, so the cost is the y and # of pencils is the x
Same as for question 7
To graph, the length depend on the time, so length is y, time is x
6. Linear
7. Not

6 0
2 years ago
WILL MARK BRAINLIEST <br><br> Which graph represents the solution set of -2y &gt; 7x + 4?
a_sh-v [17]

we have

----> inequality A

The solution of the inequality A is the interval ------> [-1,∞)

-------> inequality B

The solution of the inequality B is the interval ------> (-∞,7]

The solution of the compound inequality is

[-1,∞) ∩ (-∞,7]=[-1,7]

therefore

the answer in the attached figure

8 0
3 years ago
Read 2 more answers
Which measure of center is the best to use to compare the prices of kid socks and adult socks?
k0ka [10]

Answer:

The answer is mean

Step-by-step explanation:

The mean is the average cost of the socks, so finding the mean of both would give an average price to compare them to. :)

3 0
3 years ago
Read 2 more answers
A value 5 times a smaller number is 1 less than a larger number. their difference is 73
salantis [7]

Answer:

The numbers are 18 and 91

Step-by-step explanation:

You can translate the information to two equations:

<em>a value 5 times a smaller number is 1 less than a larger number</em>

5a = b - 1

<em>their difference is 73</em>

b - a = 73

Then you should merge one equation into the other, thereby eliminating one variable. You can do this any way you want. I choose to rewrite the first equation as:

b = 5a + 1

Now I can write 5a+1 in the second equation at the place where b was:

5a + 1 - a = 73

It is now an equation with only one variable, solve by simplifying

4a = 72

a = 18

Now b can be found using b = 5a + 1

b = 91

8 0
3 years ago
12X12= ___+144-88=___
nalin [4]
12x12=144+144-88=200 good luck!
4 0
3 years ago
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