Answer:
The area of △AON and the area of △ABC is x. The area of △AON is one-sixth part of △ABC.
Step-by-step explanation:
Let the total area of △ABC be x.
A median of a triangle divides the area of a triangle in two equal parts.
Since AM are CN are medians, therefore the area of △ACN, △BCN, △ABM and △ATM are equal, i.e., .
A centroid is the intersection point of all medians of a triangle. A centroid divides each median in 2:1.
Since CN is median and O is the centroid of the triangle, therefore CO:ON is 2:1.
Draw a perpendicular on CN from A as shown in below figure. Let the height of the pendicular on CN from A be h.
Therefore the area of △AON is one-third of △ACN.
The area of ANO is . Therefore the area of △AON is one-sixth part of △ABC.
4 is the answer king have a good day
Answer:
From the General Equation of a straight line
Y=Mx + c
where M = Slope of the line
c= Intercept on Y axis
y=-4.2x-80
Comparing with the Eqn of a straight line
Slope = -4.2
From the Options the answers are in Fractions
You can easily convert this figure to fraction by Moving the decimal to the back once and then divide by 10
Then we have -42/10
Reducing Further
you have = -21/5.
Option D✅
Answer:
w = -10,6
Step-by-step explanation:
w(4+w)=60
4w + w^2 -60 = 0
w^2 +4w -60 = 0
w^2 +10w -6w -60 = 0
w(w+10) -6(w+10) = 0
w = -10, 6
I'm sorry I really don't know I'm not really good with math that's why I got them brainly for other people's help because I really not that cool math and I'm homeschooled