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ahrayia [7]
3 years ago
8

The expression 12 x y z - 45 is a what

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0
^n=1/square root of 59 (535) ,if that makes sense its hard to type it
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2 years ago
Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not
Verizon [17]

Answer: \left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-2}{4-1}

   = -\frac{5}{3}

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = -\frac{5}{3}(x - 1)

y - 2 = -\frac{5}{3}x + \frac{5}{3}

y      = -\frac{5}{3}x + \frac{11}{3}

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ -\frac{5}{3}x + \frac{11}{3}

8 ___ -\frac{5}{3}(-2) + \frac{11}{3}

8 ___ \frac{1}{3}

8 > \frac{1}{3}

so ≤ makes the statement False

⇒ y ≤ -\frac{5}{3}x + \frac{11}{3}

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.  

y < 8   or  x > -2 are two examples.


---> I just realized that the system can be simpler than what I did above:

\left \{ {{x>-2} \atop {y < 8}} \right



4 0
3 years ago
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