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2 years ago

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Algebra 2 Semester Exam Extra Credit!!!

1 answer:

stealth61 [152]2 years ago

4 0

The message is supposed to say HAPPYNEWYEAR.

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Glenda and Penny are doing

Volgvan

Answer:

It depends on how many inches they are from the finish line.

Step-by-step explanation:

However, they will be at the same distance at 90 inches when Glenda hops 5 times. 18 x 5 = 90. Penny will also make it to 90 inches when she hops 6 times. 15 x 6 = 90. Then, you will subtract 90 inches from how long the race is in inches.

Hope this helps!

4 0

2 years ago

Help please someone I need all answers please

snow_tiger [21]

17. 8/10 is equal to .8 not .08
18a. False
18b. True
18c. False
18d. False
18e. True
19. 0.02
20. No, the zero needs to be in the tenths place or else the decimal (.2) would become 2/10.
21. 17/100
22. Words- Ten hundredths
Fraction- 10/100
Decimal- .10

5 0

3 years ago

Luke is 5 years younger than 3 times in Sydney's age in the situation what does 3s represnt

Fudgin [204]

3s is 3 times sydneys age. so the equation would be 3s-5

8 0

3 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

2 years ago

Evaluating expressions:<br> 1. x + 9 when x = 3

balu736 [363]

⇨ The numeric value of this expression = 12.

<h3> </h3>

To solve this expression, just <u>replace '</u><u>x</u><u>'</u> by the <em>indicated value</em>, being the number 3, and <em>perform</em> the <em>indicated </em>math <em>operations</em>.

${\large \displaystyle \sf {1 \cdot x+9 }}$

${\large \displaystyle \sf {x=3 }}$

${\large \displaystyle \sf {1 \cdot 3+9 }}$

${\large \displaystyle \sf { 3+9 }}$

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \ }}}}}}\\\\$

Therefore, we can conclude that, the correct value of this expression = 12.

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \ }}}}}}\\\\$

<h3><em>Hope this helps! ❤️</em></h3>

4 0

2 years ago