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ryzh [129]
3 years ago
10

Evaluate each expression if a = 12, b = 9, and c = 4.

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

168

Step-by-step explanation:

2c(a+b) = 2 . 4 . (12 + 9) = 2 . 4 . 21 = 8 . 21 = 168

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What is the slope of the line through (-7.-2) and (-6,7)
Xelga [282]

Answer:

gradient = 9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Shanley would like to give $5 gift cards
Serjik [45]

Answer:

$5x + $4y ≤ $120

let x = 10

y = 5

$70  ≤ 120

Step-by-step explanation:

Note that

> means greater than

< means less than

≥  means greater or equal to

≤ means less than or equal to

the total amount Shanley has is $120. She can spend less than this amount or the amount exactly. So, the inequality sign to be used is ≤

$5x + $4y ≤ $120

let x = 10

y = 5

(50) + 20  ≤ 120

$70 ≤  120

4 0
3 years ago
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

8 0
3 years ago
A machine that fills 12-quart size packages of ice cream runs 8 hours a day, 7 days a week. The machine fills 900 ice cream pack
otez555 [7]

Answer:

Number of ice cream packaged each week = 604,800 Ice cream

Step-by-step explanation:

Given:

One package = 12 ice cream

Per day packing = 8 hour

Number of days work in a week = 7 days

Per hour packing = 900 package

Find:

Number of ice cream packaged each week :

Computation:

⇒ Number of ice cream packaged each week = Number of days work in a week × Per day packing hour × Per hour packing × Per package ice cream

⇒ Number of ice cream packaged each week = 7 × 8 × 900 × 12

⇒ Number of ice cream packaged each week = 604,800 Ice cream

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!!!
trapecia [35]

The numbers inside the parenthesis is the value of x, uses the equation associated with the value of x and solve.

H(1) Since 1 fits 1≤x≤3 use x^3

x^3 1^3 = 1

h(1) = 1

h(4) 4 fits x >3, so use 5

h(4) = 5

5 0
3 years ago
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