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mixas84 [53]
2 years ago
12

Help me plz I would really appreciate it!

Mathematics
1 answer:
LenKa [72]2 years ago
7 0
  • Given,
  • x =  \frac{7}{9}  \:  \:  \: y =  \frac{5}{6}   \\  \\   - 2y + x \\  =  - 2( \frac{5}{6} ) +  \frac{7}{9}  \\  =  -  \frac{5}{3}  +  \frac{7}{9}  \\  =   \frac{ - 15 + 7}{9}  \\  =  \frac{ - 8}{9}

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Answer:

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4 years ago
What goes on the first blank tick mark?
Lubov Fominskaja [6]

Answer:

24

Step-by-step explanation:

The number line should read 18, 24, 30, 36, 42. There is a spacing of 6 units between each tick mark.

Good luck.

Hope this helps!

7 0
3 years ago
A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal
Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals 0.0003724L_{i} where L_{i} is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}

We have

\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}

Applying values we get

\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}

Similarly axial strain is given by

\epsilon _{diam}=\frac{\sigma _{axial}}{E}

\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}

Applying values we get

\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}

Hence The effect of axial strain along the diameter is given by

-\nu \epsilon _{axial}

Applying values we get

-\nu \epsilon _{axial}=-0.27\times \frac{2.5}{3088}=-0.0002185

hence

\epsilon _{D} =\frac{5}{3088}-0.0002185\\\\\epsilon =0.00140

Now by definition of strain we have

\epsilon _{D} =\frac{D_{f}-D_{i}}{D_{i}}\\\\\therefore D_{f}=D_{i}+\epsilon D_{i}\\\\D_{f}=2.5+0.0014\times 2.5\\\\\therefore D_{f}=2503.5mm

Increase in the diameter is thus 3.5 mm

Using the same procedure for axial strain we have

\epsilon_{axial} =\epsilon_{axial}-\nu \epsilon _{diam}

Applying values we get

\epsilon_{axial} =\frac{2.5}{3088}-0.27\times \frac{5}{3088}

\epsilon_{axial} =0.0003724

Now by definition of strain we have

\epsilon _{axial} =\frac{L_{f}-L_{i}}{L_{i}}\\\\\therefore \Delta L=0.0003724L_{i}

where L_{i} is the initial length of the cylinder.

6 0
4 years ago
soda pop is on sale at a price $10 for 3 packs. What is the scale factor that can be used to find out how much it would cost to
forsale [732]

Answer:

My answer is:

Step-by-step explanation:

150$ for 15

8 0
3 years ago
What is 48 times 10 =??????
Agata [3.3K]
The correct asnwer is 480. I hope this was useful! (:
6 0
3 years ago
Read 2 more answers
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