Answer: In June 2097
Step-by-step explanation:
According to the model, to find how many years t should take for 
we must solve the equation 
. Substracting 21100 from both sides, this equation is equivalent to 
.
Using the quadratic formula, the solutions are 
and 
. The solution 
can be neglected as the time t is a nonnegative number, therefore 
.
The value of t is approximately 85 and a half years and the initial time of this model is the January 1, 2012. Adding 85 years to the initial time gives the date January 2097, and finally adding the remaining half year (six months) we conclude that the date is June 2097.
9:1 because you divide both sides by 8. Hope this helps :)
Formula y-y1= m(X-X1)
Since its parallel the m is 1/2
The -6 is X1 and the 4 is y1
Okay now do formula
Y-4= 1/2(X--6)
Y-4= 1/2X+3
Add 4
Y= 1/2x +7
Amount after 9 years = 3600( 1 + 0.024)^9 = $4456.58
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
