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3 years ago

13

Write in exponential notation 6 times 6 times 6 times 6 times 6

2 answers:

Darina [25.2K]3 years ago

7 0

Exponent form : 6^5

explanation :
we are given five 6's , so we simply start out with the number that is being multiplied over and over again .
which in this case , is 6.

6 • 6 • 6 • 6 • 6 = 7776

To make things easier though, we write repetitive numerals in exponent form. You will still get the same answer either way .

6^5 = 7776

answer : 6^5

jeka943 years ago

4 0

answer: 6^5

Tip: however many times you see the the number .hat's the exponential notation.

Example: 3x3x3x3x3x3x3=3^7

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How can the logarithmic expression be rewritten?

andrey2020 [161]

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True.

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7 0

3 years ago

If nine times a certain number is subtracted from 7 the result is 52. Find the number.

mezya [45]

Answer:

Let the number to find be x

7 - 9x = 52

-9x = 52-7

- 9x = -45

Divide by - 9

x = 5

The number is 5

Hope this helps.

6 0

4 years ago

Read 2 more answers

a cube has sides with the following number: 3,3,6,9,,7,8. what is the probability of getting a factor of 9 when rolled?

muminat

Answer:

The probability of rolling a factor of 9 is 1/2, or 50%.

Step-by-step explanation:

The number 9's factors are 1, 3, and 9. Three of the six sides of the cube have a factor of 9. Therefore 3/6 of the sides are factors of nine.

Simplify 3/6 to 1/2 to get a probability of 50%.

5 0

2 years ago

Find the slope of the line that contains the following points.<br> R(-3,5), S(3,-2)

Goryan [66]

Answer:

-7/6

Step-by-step explanation:

var y/ var x

5 to -2 is variation y ----> -7

-3 to 3 is variation x ---> 6

4 0

4 years ago

Read 2 more answers

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago