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3 years ago

What is the answer for. -3x > -15

Mathematics

1 answer:

lana [24]3 years ago

7 0

Answer:

x<5

Step-by-step explanation:

-3x > -15

Divide -3 on both sides:

$\frac{-3x}{-3} >\frac{-15}{-3}$

x<5

*Note the sign switches because

the x is negative. The sign only

switches when the number you

are dividing by is negative.*

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Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = $\frac{p x_{2}+q x_{1}}{p+q}$

y = $\frac{p y_{2}+q y_{1}}{p+q}$

From the question

$x_{1}$ = 2

$x_{2}$ = ?

x = 4

$y_{1}$ = -1

$y_{2}$ = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = $\frac{p x_{2}+q x_{1}}{p+q}$

4 = $\frac{1(x_{2})+4(2) }{1+4}$

4 = $\frac{x_{2}+8}{5}$

$x_{2}$ + 8 = 20

$x_{2}$ = 12

Also

y = $\frac{p y_{2}+q y_{1}}{p+q}$

1 = $\frac{y_{2}+4(-1)}{5}$

$y_{2}$ - 4 = 5

$y_{2}$ = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

5 0

3 years ago

LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) = $\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}$

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

$(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)$

Required equation: $y-1=\dfrac32(x+3)$

8 0

3 years ago

given the two points (-24,7) and (30,25) a. What is an equation passing through the points? b. Is (51, 33) also on the same line

kicyunya [14]

Part 1) Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
find the slope m
m=(y2-y1)/(x2-x1)---->m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15

the answer Part 1) is
y=(1/3)*x+15

Part 2) Is (51, 33) also on the same line?
if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
the point does not belong to the given line

the answer Part 2) is
the point does not belong to the given line

see the attached figure