<span>A = P(1+r/2)^2t
A/P = (1+r/2)^2t
ln(A/P) = 2t ln((1+r/2))
ln(A/P)/ln(1+r/2) =2t
ln(9000/4190.51)/ln(1+0.052/2)=2t
t=15 yrs
therfore ans is C.14 years ,11 months</span>
Answer:
D
Step-by-step explanation:
TAN is opposite/adjacent
15/8
Answer:
50 kg
Step-by-step explanation:
Given that:
SMALL HELICOPTERS:
Weight of small helicopters = 3kg
Weight of shipping container = 20kg
LARGE HELICOPTERS:
Weight of large helicopters = 4kg
Weight of shipping container = 10kg
Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight
Shipping weight :
(Weight per helicopter * number of helicopter) + weight of shipping container
Shipping weight of Small helicopters :
(3kg * s) + 20
Shipping weight Large helicopters :
(4kg * S) + 10
Shipping weight of Small helicopters = shipping weight of large helicopters
3s + 20 = 4s + 10
20 - 10 = 4s - 3s
10 = s
Hence, member of shipped helicopters = 10
Total shipping weight :
(4 * S) + 10
(4*10) + 10
40 + 10 = 50kg
Answer:
Distance cover by Frank and family each day = 300 miles per day
Step-by-step explanation:
Given:
Total distance cover by Frank and family = 3,000 miles
Number of days = 10
Find:
Distance cover by Frank and family each day
Computation:
Distance cover by Frank and family each day = Total distance cover by Frank and family / Number of days
Distance cover by Frank and family each day = 3,000 / 10
Distance cover by Frank and family each day = 300 miles per day
Use the formula 1/2(base1+base2)height. Substitute the values.
