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Ghella [55]
3 years ago
8

WILL GIVE BRAINLIEST IF YOUR RIGHT!!!!

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer: R+I, I+I, R×I will always be irrational.

Step-by-step explanation: Surprisingly, I×I could be rational. For example √3 ×√3 = 3

R×R and R+R should obviously be rational.

Crazy boy [7]3 years ago
5 0

Answer:

I.I

R.R

Step-by-step explanation:

R.R would be R.RRRR......

and I.I would be I.IIII...

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What value of t makes P(t) = 21?<br> A. 1<br> B. 2<br> C. 3<br> D. 4
Ksju [112]
I don't understand the question, but I did get this:
t=21/P
Hope this helps!!
5 0
3 years ago
Explain in your own words how a rocket is able to lift off
fredd [130]
When the rocket accelerates up, the thrust is greater than the combined lift and drag, therefore making it go upward. Thrust from the engine / or whatever the power source is makes it lift.

Hope that helps!
8 0
3 years ago
Calculate the pay for the following day of a<br> weekly time card given a wage of $12.50/hr.
Elenna [48]

The one day pay is $106.25 rounded to the nearest hundredth.

<u>Step-by-step explanation:</u>

<u>From the table shown :</u>

  • The timing shown in the morning is from 8:00 to 12:15
  • The number of hours worked in the morning = 4 hours 15 minutes.

It is given that, the pay is $12.5 per hour.

Therefore, the pay earned in the morning = No.of hours × pay per hour.

⇒ 4 hours × 12.5 = $50

⇒ (15 mins / 60 mins) × 12.5 = $3.125

⇒ 50+3.125

⇒ 53.125

  • The timing shown in the afternoon is from 8:00 to 12:15
  • The number of hours worked in the morning = 4 hours 15 minutes.

Therefore, the pay earned in the afternoon = No.of hours × pay per hour.

⇒  4 hours × 12.5 = $50

⇒ (15 mins / 60 mins) × 12.5 = $3.125

⇒ 50+3.125

⇒ 53.125

The pay for 1 day = pay earned in the morning section + pay earned in the afternoon section.

⇒ 53.125 + 53.125

⇒ 106.25

∴ The one day pay is $106.25 rounded to the nearest hundredth.

7 0
3 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
Can someone explain how to do this?
Tems11 [23]
         x+7
------------------- =       
  x^2+4x -21

         x+7
= -------------------
    (x+7)(x-3)

       1
= ----------  where x is not equal -7 and 3
    x - 3

answer is A. first choice
4 0
3 years ago
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