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LiRa [457]
3 years ago
6

How do you solve this?? Please help!

Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

f = (f1 f2) / (f1 + f2)

f(f1 + f2) =  f1 f2

f f 1 + f  f 2 = f1 f 2

f1 f2 - f f2 = f f1

f2 (f1 - f)  = f f1

f2 = (f f1) / (f1 - f) <==== solution


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The distance between Henry's house and his school is 648 feet. How many yards are equivalent to 648 feet?
vlabodo [156]

Answer:

216 yards

Step-by-step explanation:

There are 3 feet in a yard, so the number of yards is equal to the number of feet divided by 3.

648/3 = 216

5 0
3 years ago
Read 2 more answers
Why does 0.25 x 0.4 have a one decimal place in the product
Dafna11 [192]
The product of these numbers are 0.100
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COMMON SENSE
4 0
3 years ago
If the total cost plus shipping is greater than $35,then you receive a 10% discount off the original selling price. Do you quali
RUDIKE [14]

<u>It's not clear what is the specific requirement of the question, but I'll assume a couple of situations to help you with your real problem.</u>

Answer:

$45 (qualified)

$30 (did not qualify)

Step-by-step explanation:

<u>Percentage Calculations</u>

Relative quantities are usually expressed as percentages (%). We say x percent of y is the proportion xy/100. When discounts or surcharges are applied, they are subtracted or added to the original quantity.

The question explains I receive a 10% discount off the original selling price if the total cost plus shipping is greater than $35. Let's assume the total cost plus shipping is $50. Since it's greater than $35, it qualifies for a discount. The discount is 10% of $50 = (10)(50)/100= $5. So the new total cost will be $50 - $5 = $45

Let's suppose now the total cost+shipping is $30. Since it's not greater than $35, no discount will be applied and we have to pay $30

7 0
3 years ago
3x^2-5x-7 find the sum and product​
Bad White [126]

Answer:

s =  \frac{5}{3}

p =  \frac{7}{3}

Step-by-step explanation:

for this equation

a=3

b= -5

c = -7

The sum of equal to

-  \frac{b}{a}

and the product is equal to

\frac{c}{a}

. All you do is replace the values. You can prove both of those using the quadratic formula.

3 0
3 years ago
Exhibit 6-2 the weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 poun
Evgen [1.6K]
The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.

95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
5 0
3 years ago
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