Answer:
B
Step-by-step explanation:
Because i took the test
Answer:
10
Step-by-step explanation:
I assume it's a rectangle, therefore:
P = 50
a = 15 ft
b = ?
P = 2a + 2b
50 = 2 * 15 + 2b
50 = 30 + 2b
2b = 50 - 30
2b = 20
b = 10
Quantify of sand in a bag =



Quantity of sand that escapes in every 10 minutes :-

Quantity of sand that will escape in 20 minutes :-




Quantity of sand that will remain in the sand bag :-






Answer:
6x^3 - 2x^2 -11x +4
Step-by-step explanation:
(3x-4)(2x^2+2x-1)
Multiply 3x by the second term
3x* (2x^2+2x-1)
6x^3 +6x^2 -3x
Multiply -4 by the second term
-4*(2x^2+2x-1)
-8x^2 -8x+4
Add these together, lining up the terms
6x^3 +6x^2 -3x
-8x^2 -8x+4
----------------------------------
6x^3 - 2x^2 -11x +4
Answer:
f(2) = g(2)
General Formulas and Concepts:
<u>Alg I</u>
- Reading a Cartesian Plane
- Identifying Coordinates
- Solutions of systems of equations
Step-by-step explanation:
We see from the graph that f(x) and g(x) intersect at x = 2. Therefore, the point at x = 2 would be equivalent in both graphs/be a solution to both equations.
Therefore, f(2) must equal g(2), as they intersect each other at that point and have the same value of 0.