Answer:
A baseball diamond is a square with sides of 90 feet. What is the distance to the nearest tenth of a foot between home and second base?
Step-by-step explanation:
127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3
14,800=60x+16y
x+y=441
that implies y=441-x so
14,800=60x+16(441-x)
14,800=60x+16*441-16x
14,800-16*441=44x
7744=44x
x=176 kids and 441-176 adults
Answer:
b = -ax + 4x + 2
Step-by-step explanation:
8x - 3x + 2 - x = ax + b
~Combine like terms
4x + 2 = ax + b
~Subtract ax to both sides
4x - ax + 2 = b
~Rewrite
b = -ax + 4x + 2
Best of Luck!
Answer:
275
Step-by-step explanation:
550 divided by 2 is 275.
